How to Remove a File Path from a Filename in Go?

Removing Path from a Filename in Go

When dealing with files in Go, you may encounter scenarios where you need to extract only the file name without its path. This can be achieved through the filepath package.

Let's consider an example where you have a string line containing both the path and filename:

line := "/some/path/to/remove/file.name"

Using strings.LastIndex(line, "/") to find the position of the last slash character returns a number, which is the index of the slash in the string. However, this does not directly provide the file name without the path.

The solution lies in utilizing the filepath.Base function, which takes a file path as an argument and returns the file's base name, effectively removing the path portion:

file := filepath.Base(line)

By invoking this function, you obtain the file name without the path. To demonstrate, consider the following example:

path := "/some/path/to/remove/file.name"
file := filepath.Base(path)
fmt.Println(file) // Output: file.name

As you can see, filepath.Base extracts only the file name, leaving you with the desired result. This is useful when you need to perform operations specifically on the file name or when you want to remove unnecessary path information.

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