How Can I Efficiently Extract a Filename from a File Path in Go?

Extracting Filename from Path

In Go, the file name and path are often stored together in a string. Removing the path to obtain just the file name can be a common task. This article addresses such a scenario, explaining how to accomplish it effectively.

The initial approach of using strings.LastIndex to identify the last slash character is not ideal because it returns the character's index instead of the desired file name. To correctly isolate the file name, we recommend utilizing the filepath.Base function.

Using filepath.Base for Filename Extraction

The filepath.Base function accepts a path and extracts the final element, which typically represents the file name. It is an efficient method for this specific task.

import (
    "fmt"
    "os"
    "path/filepath"
)

func main() {
    path := "/some/path/to/remove/file.name"
    file := filepath.Base(path)
    fmt.Println(file) // Output: file.name
}

Playground for Verification

We provide a Golang playground for you to experiment with this code: http://play.golang.org/p/DzlCV-HC-r.

By employing filepath.Base, you can easily separate the filename from its path in Go, adhering to the convention of representing file names without the preceding directory path.

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