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HomeDatabaseMysql TutorialWhy Does My PHP Code Show 'Resource ID #6' Instead of MySQL Query Results?

Why Does My PHP Code Show

Echoing a "Resource ID #6" from MySQL Results in PHP

In PHP, the mysql_query() function returns a resource ID when executing a SQL statement. This resource ID represents the result set of the query. To extract the actual result, you need to use a fetch function.

For example, to echo the result of SELECT TIMEDIFF(NOW(), '" . $row['fecha'] . "'); and avoid getting "Resource ID #6," use the following code:

$result = mysql_query(sprintf("SELECT TIMEDIFF(NOW(), '%s') as time_delta", $row['fecha']));
if ($result) {
  $data = mysql_fetch_assoc($result);
  echo $data['time_delta'];
}

The mysql_fetch_assoc() function retrieves the first row of the result set as an associative array. You can then access the result using the column name as the array key (e.g., $data['time_delta']).

Note:

It's generally discouraged to use the deprecated mysql_* functions. Instead, consider using PDO with PDO_mysql or mysqli.

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