Home >Backend Development >C++ >Why Does `atof` Return Zero When Converting a `std::string` to `double`?
When attempting to convert a std::string to a floating-point type such as float or double using the atof function, you may encounter unexpected results. Here's a common issue and its solution:
std::string num = "0.6"; double temp = (double)atof(num.c_str());
In the above code, the atof function returns zero instead of the expected value of 0.6. This occurs because atof is a C function that expects a C-style string (char *) as its argument. However, num.c_str() returns a pointer to the first character in the std::string object, which is an object type.
To resolve this issue, you should pass a C-style string directly to atof. Here's the corrected code:
std::string num = "0.6"; double temp = ::atof(num.c_str());
The double colon (::) before atof indicates that the atof function is a global function declared in the std namespace.
While the above solution using atof is valid, it's worth noting that there are alternative methods that may provide additional functionality or performance benefits. For example:
However, it's important to evaluate the performance implications of these alternative methods, as they may come with additional overhead compared to using atof.
If your project uses the Qt framework, you can take advantage of the built-in QByteArray::toDouble method. It's typically faster for converting from const char* data than using std::stringstream.
QString winOpacity("0.6"); double temp = winOpacity.toDouble();
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