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Java Class Variable Override Conundrum
Consider the following Java code snippet:
<br>class Dad {</p> <pre class="brush:php;toolbar:false">protected static String me = "dad"; public void printMe() { System.out.println(me); }
}
class Son extends Dad {
protected static String me = "son";
}
public void doIt() {
new Son().printMe();
}
The code appears to define a class variable named "me" in both the "Dad" and "Son" classes. When calling "doIt()", one might expect the code to print "son" since "Son" is a subclass of "Dad". However, this is not what happens.
Why Does "doIt()" Print "dad"?
In Java, class variables cannot be overridden. Instead, they are hidden. Specifically, when declaring a class variable with an existing name in a subclass, the subclass hides the inherited class variable, effectively creating a new class variable with the same name but distinct from its parent class.
Overriding vs. Hiding
Overriding involves providing a different implementation for a method in a subclass that overrides the method in the superclass. In contrast, hiding involves using the same variable name in a subclass, but it hides the variable inherited from the superclass and creates a new variable local to the subclass.
How to Print "son"?
To achieve the desired behavior of printing "son", one cannot override the class variable. Instead, one can use other inheritance techniques such as:
Example with Constructor Argument:
<br>public class Person {</p> <pre class="brush:php;toolbar:false">private String name; public Person(String name) { this.name = name; } public void printName() { System.out.println(name); }
}
In this example, the class "Person" has a constructor that sets the name. This allows one to create subclasses of "Person" and pass specific values for the name.
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