How Do I Correctly Pass Arrays by Reference in C ?

Passing Arrays by Reference in C

In C , arrays are passed by reference by default. However, the syntax for doing so can be confusing for some programmers.

Using the syntax:

void foo(double& *bar)

to pass an array by reference is not allowed in C . Instead, use this syntax:

void foo(double (&bar)[10])
{
}

This prevents potential errors by restricting the array size to be exactly 10.

To pass an array of arbitrary size by reference, use a template function that captures the size at compile time:

template<typename T, size_t N>
void foo(T (&bar)[N])
{
    // Size of bar is N
}

For better code readability and functionality, consider using std::vector or std::array instead of raw arrays.

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