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Achieving a Single Instance Executable with Golang on Windows
Running multiple instances of an executable can lead to unexpected behaviors and resource contention. To prevent this, you may wish to restrict your Golang application to a single active instance.
Using Global Mutex for Instance Control
A common approach to enforce single instance execution is through the use of a global mutex. A mutex, or mutual exclusion object, allows only one process to gain exclusive access to a shared resource at any given time. In this case, our shared resource is the running executable.
Implementation on Windows
To create a global mutex in Golang for Windows, you can utilize the CreateMutexW function provided by the kernel32.dll. This function takes several arguments, including the name of the mutex. For cross-user session compatibility, it's recommended to prefix the mutex name with "Global".
In the provided code snippet, a function called CreateMutex is defined that abstracts the CreateMutexW function. You can use this function to create a global mutex by passing a unique name, such as "SomeMutexName".
Here's the modified code snippet:
import ( "syscall" "unsafe" ) var ( kernel32 = syscall.NewLazyDLL("kernel32.dll") procCreateMutex = kernel32.NewProc("CreateMutexW") ) func CreateMutex(name string) (uintptr, error) { ret, _, err := procCreateMutex.Call( 0, 0, uintptr(unsafe.Pointer(syscall.StringToUTF16Ptr(name))), ) switch int(err.(syscall.Errno)) { case 0: return ret, nil default: return ret, err } } // mutexName starting with "Global\" will work across all user sessions _, err := CreateMutex("SomeMutexName")
By creating and setting a global mutex, your Golang application can ensure that only one instance is running at a time. If another instance attempts to execute, it will be blocked until the initial instance terminates, effectively restricting the executable to a single active instance.
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