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Why Does My Go Regex Match Fail, But Python\'s Succeeds?

Susan Sarandon
Susan SarandonOriginal
2024-11-26 03:18:10277browse

Why Does My Go Regex Match Fail, But Python's Succeeds?

Regex Match Failure in Go

A user encounters an issue where a regular expression pattern fails to match in Go. The code snippet attempts to validate a string of the form "parameter=0xFF", following the regex pattern "^. =b0xA-Fb$". However, the MatchString() function returns false and a nil error, unlike in Python where the match is successful.

Debugging the Go Code

To resolve the issue, the user should consider using a raw string literal as the pattern string. In Go, raw string literals are enclosed in backticks '`' instead of standard quotation marks '"'. This convention prevents the escape character '' from being interpreted within the string.

Corrected Go Code

The corrected Go code using a raw string literal is:

package main

import (
    "fmt"
    "regexp"
)

func main() {
    var a string = "parameter=0xFF"
    var regex string = `^.+=\b0x[A-F][A-F]\b$`
    result, err := regexp.MatchString(regex, a)
    fmt.Println(result, err)
}

Expected Output

After using a raw string literal, the expected output is:

true <nil>

This indicates that the input string matches the desired format, as intended.

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