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For developers seeking a straightforward approach to reversing the bit order of a byte, there are various techniques. However, identifying the simplest one requires a closer examination.
The objective is to transform bit sequences like these:
Let's explore the solution provided in the response:
unsigned char reverse(unsigned char b) { b = (b & 0xF0) >> 4 | (b & 0x0F) << 4; b = (b & 0xCC) >> 2 | (b & 0x33) << 2; b = (b & 0xAA) >> 1 | (b & 0x55) << 1; return b; }
This code utilizes a series of bitwise operations to achieve the reversal. Initially, the left four bits are swapped with the right four bits using:
b = (b & 0xF0) >> 4 | (b & 0x0F) << 4;
Next, adjacent bit pairs are swapped with:
b = (b & 0xCC) >> 2 | (b & 0x33) << 2;
Finally, adjacent single bits are swapped with:
b = (b & 0xAA) >> 1 | (b & 0x55) << 1;
This sequence of operations ultimately reverses the bit order within the byte, making this solution the simplest and most straightforward for developers to implement.
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