How Can I Efficiently Check if All or Any Elements in a Python List Meet a Specific Condition?

Checking if All Elements of a List Satisfy a Condition

In Python, determining whether all elements in a list meet a particular condition is a common task. To accomplish this, one can either employ a while loop or utilize built-in functions.

Custom While Loop Approach:

The traditional approach using a while loop involves iterating through the list and returning True if any element satisfies the condition.

def check(list_):
    for item in list_:
        if item[2] == 0:
            return True
    return False

Simplified Approach Using all():

A more concise and efficient way to perform this check is to use the built-in all() function. This function takes a generator expression as its argument, which allows it to generate values on-the-fly instead of storing them in memory.

all(flag == 0 for (_, _, flag) in items)

This expression evaluates to True if all elements in the list meet the condition, and False otherwise.

Using any() to Check for at Least One Match:

To determine if at least one element satisfies a condition, use the any() function.

any(flag == 0 for (_, _, flag) in items)

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