Why Does Using Raw Types With Generic Methods Result in Unexpected Behavior?

Understanding the Behavior of Raw Types with Generic Methods

When working with Java's generics, it is crucial to understand the implications of using raw types and their impact on generic methods. Let's delve into a specific code example and explore how raw types affect method resolution.

Consider the following code snippet, where an ArrayList of Strings is created and converted to an array:

ArrayList<string> a = new ArrayList<string>();
String[] s = a.toArray(new String[0]);</string></string>

As expected, this code compiles successfully in Java 1.6 and 1.7. However, if the ArrayList reference is declared as a raw type, an error occurs during compilation:

ArrayList a = new ArrayList();
String[] s = a.toArray(new String[0]); // Error: Argument required String[] found Object[]

In this scenario, the compiler interprets the generic method toArray(myArray) as returning an Object[] despite receiving a String[] as its argument. This behavior is quite unexpected, given that the method signature clearly specifies a type parameter .

To understand this, let's consider the Java Language Specification (JLS) section 4.8. It states that "the type of an instance method M of a raw type C that is not inherited from its superclasses or superinterfaces is the raw type that corresponds to the erasure of its type in the generic declaration corresponding to C."

In essence, when using a raw type, the compiler essentially throws away all type information, leaving only the raw representation of the class. This means that, in our example, the toArray method effectively becomes a non-generic method with an Object[] return type, even though it was originally defined as a generic method.

This loss of genericity in raw types has important implications:

• Using raw types can make your code more susceptible to runtime type errors.
• Compiler warnings may not always be triggered when using raw types, leading to potential bugs.

It is generally recommended to avoid using raw types and instead rely on generics for type safety and flexibility. However, understanding the behavior of raw types can help you troubleshoot issues and make informed decisions in specific scenarios.

The above is the detailed content of Why Does Using Raw Types With Generic Methods Result in Unexpected Behavior?. For more information, please follow other related articles on the PHP Chinese website!