How do you pass dictionary values as individual parameters to a Python function?

Passing Dictionaries as Keyword Parameters

In Python, passing dictionaries to functions can be advantageous when you want to provide multiple parameters with specific key-value pairs. However, when the goal is to pass individual values for each parameter, a straightforward approach might not yield the expected results.

Scenario 1: Passing a Dictionary with a Single Key-Value Pair

Consider the following code:

d = dict(param='test')

def f(param):
    print(param)

f(d)

In this scenario, the expected output is 'test', but instead, the code prints '{'param': 'test'}'. To obtain the desired output, the ** operator can be used to unpack the dictionary.

Revised Code:

d = dict(param='test')

def f(param):
    print(param)

f(**d)

Now, the code will print 'test' as intended.

Scenario 2: Passing a Dictionary with Multiple Key-Value Pairs

A similar issue arises when passing a dictionary with multiple key-value pairs to a function expecting multiple parameters.

d = dict(p1=1, p2=2)

def f2(p1, p2):
    print(p1, p2)

f2(d)

The expected output is '1 2', but instead, the code outputs '{'p1': 1, 'p2': 2}'. To resolve this, the ** operator is again utilized to unpack the dictionary.

Revised Code:

d = dict(p1=1, p2=2)

def f2(p1, p2):
    print(p1, p2)

f2(**d)

After these modifications, the code will correctly print '1 2'.

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