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In JavaScript, awaiting multiple async functions may give the impression that they execute sequentially rather than concurrently. This raises the question: how can we achieve parallel execution of these functions?
To execute async functions in parallel, you can employ the Promise.all() function. It takes an array of promises as an argument and returns a single promise that resolves when all the promises in the array resolve.
await Promise.all([someCall(), anotherCall()]);
In this code, both someCall() and anotherCall() are called simultaneously, and the script proceeds only when both functions have finished executing.
If you want to access the results of the parallel async calls, you can destructure the array returned by Promise.all():
let [someResult, anotherResult] = await Promise.all([someCall(), anotherCall()]);
It's important to note that Promise.all() follows a "fail-fast" approach. If any of the promises in the array rejects, the entire Promise.all() promise will reject with the error from the first failed promise:
// If any of the promises fails, it will reject Promise.all([happy('happy', 100), sad('sad', 50)]).then(console.log).catch(console.log);
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