How to Call Static Methods in ES6 Classes: Constructor vs Class Name?

How to Call Static Methods in ES6 Classes

When dealing with static methods in ES6 classes, there are two primary approaches to invoke them. The choice between the two depends on your specific requirements and expectations.

Using the Constructor

The first method involves using the constructor function of the class. For instance, in the following example:

class SomeObject {
  constructor(n){
    this.n = n;
  }

  static print(n){
    console.log(n);
  }

  printN(){
    this.constructor.print(this.n);
  }
}

To call the static print method, you can use this.constructor.print(n) within instance methods, как показано в printN.

Using the Class Name

The second approach is to invoke the static method directly through the class name. Continuing with the previous example:

SomeObject.print(n);

Inheritance Considerations

When overriding static methods in subclasses, the two approaches can have different implications:

• Using the class name refers to the static property of the current class and overrides if present. This is similar to Java's approach.
• Using this.constructor refers to the static property of the current instance's class, including any potential overrides. This is similar to Python's behavior.

Which Approach to Choose?

The most suitable approach depends on your desired behavior. If you want static methods that always refer to the class they belong to, use the explicit class name. If you prefer dynamic dispatch, where overridden static methods are used, employ this.constructor.

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