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Implicit Type Conversion with Templates
The query explores the issue of enabling implicit type conversion in template classes. Consider the case of a template class A with a constructor that accepts an integer.
template <unsigned int m> class A { public: A(int); };
Furthermore, there's an operator ' ' that returns an instance of A given two A objects.
template<unsigned int m> A<m> operator+(const A<m>&, const A<m>&) { return A<m>(0); }
The problem arises when attempting to implicitly convert an integer to an A object. For instance, the following code attempts to do so, but the compiler throws an error:
A<3> a(4); A<3> b = a + 5; A<3> c = 5 + a;
Solution
The solution lies in exploiting a feature of the language that allows the definition of non-member friend functions inside a class definition. In the case of templates, for each instantiation of the template, the compiler generates a free non-template function with a signature obtained by substituting the real types of the instantiation in the friend declaration:
template <typename T> class test { friend test operator+(test const &, test const &); // [1] }; test<int> t; // [2]
In [1], the compiler allows the definition of the friend function inside the class scope. Then, in [2], when the template is instantiated, the compiler generates a free function:
test<int> operator+(test<int> const &, test<int> const &) { return test<int>(); }
This non-template function is always defined, regardless of whether it's used or not.
Magic of Implicit Conversion
The "magic" here lies in the following aspects:
However, this solution also has some limitations:
Despite these limitations, this solution provides an elegant way to enable implicit conversion within template classes, allowing for more flexible and convenient code.
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