How Can I Efficiently Send 100,000 HTTP Requests in Python?

Sending HTTP Requests Efficiently in Python

When faced with the task of sending a large number of HTTP requests in Python, the question of efficiency arises. The problem described involves sending 100,000 requests from a file of URLs, obtaining their status codes, and printing them. Given the large number of requests, finding the fastest method becomes crucial.

Twisted vs. Non-Twisted Approach

For Python 2.6, a non-Twisted solution using threading provides a faster and simpler alternative. The "twistedless" code provided in the answer employs a thread pool of 200 threads, ensuring that multiple HTTP requests are processed concurrently.

Implementation Details

The approach uses a Queue object (q) to manage the URLs. A pool of threads is created, each executing the doWork function. This function retrieves a URL from the queue, retrieves its status code using getStatus, and performs an action with the result.

getStatus establishes an HTTP connection, sends a HEAD request, and retrieves the status code.

doSomethingWithResult handles the status code and URL. In the provided example, it simply prints them.

Performance Comparison

The provided code has been demonstrated to be faster than a Twisted solution, utilizing fewer CPU resources. This is attributed to the simpler implementation and the absence of Twisted's overhead.

Additional Considerations

When utilizing concurrency in Python, it is important to consider factors such as thread safety, resource management, and exception handling. The provided code handles exceptions within the getStatus function, and the main program terminates gracefully upon a keyboard interrupt.

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