Home >Backend Development >Golang >Why does `fmt.Sprintf` produce unexpected output when using a variadic parameter in a wrapper function?
Unraveling Variadic Parameters in Wrapper Functions
Variadic functions in Go play a crucial role in accepting an arbitrary number of arguments. To utilize this feature effectively, it's essential to understand how these parameters are handled.
Consider the example of a fmt.Fprintf wrapper function:
func Die(format string, args ...interface{}) { str := fmt.Sprintf(format, args) fmt.Fprintf(os.Stderr, "%v\n", str) os.Exit(1) }
When invoking this function with Die("foo"), a rather unexpected output emerges: foo%!(EXTRA []interface {}=[]). This perplexing suffix can be attributed to the way variadic parameters are passed.
By design, variadic functions receive arguments as a slice of their respective type. In this case, the Die function accepts a []interface{} slice named args. However, when subsequently passing this argument to fmt.Sprintf, it's treated as a single entity of type []interface{}, rather than the intended individual values.
To rectify this, the ... syntax should be employed as seen below:
str := fmt.Sprintf(format, args...)
Using this approach ensures that each value within args is passed to fmt.Sprintf as a separate argument, mimicking the behavior when receiving them in the Die function. This crucial distinction aligns with the Go language specification and guarantees the expected output.
The above is the detailed content of Why does `fmt.Sprintf` produce unexpected output when using a variadic parameter in a wrapper function?. For more information, please follow other related articles on the PHP Chinese website!