Home >Backend Development >C++ >How do you calculate clockwise angles between two vectors directly?

How do you calculate clockwise angles between two vectors directly?

Mary-Kate Olsen
Mary-Kate OlsenOriginal
2024-11-14 16:19:02342browse

How do you calculate clockwise angles between two vectors directly?

Calculating Clockwise Angles Directly

Calculating the clockwise angle between two vectors is often addressed using the dot product, which determines the inner angle (0-180 degrees). However, if you prefer a direct method, here are the steps to consider:

2D Case

Just like the dot product measures the cosine of the angle, the determinant provides the sine of the angle. The clockwise angle can be computed as:

dot = x1*x2 + y1*y2  # Dot product between [x1, y1] and [x2, y2]
det = x1*y2 - y1*x2  # Determinant
angle = atan2(det, dot)  # atan2(y, x) or atan2(sin, cos)

The angle's orientation aligns with the coordinate system, with positive signs indicating clockwise angles. Swapping the inputs changes the orientation and hence the sign.

3D Case

For 3D vectors, the two vectors define an axis of rotation perpendicular to both. Since this axis has no fixed orientation, the angle of rotation's direction cannot be uniquely determined. A common convention involves orienting the axis to produce positive angles. In this scenario, the dot product of normalized vectors suffices:

dot = x1*x2 + y1*y2 + z1*z2  # Between [x1, y1, z1] and [x2, y2, z2]
lenSq1 = x1*x1 + y1*y1 + z1*z1
lenSq2 = x2*x2 + y2*y2 + z2*z2
angle = acos(dot/sqrt(lenSq1 * lenSq2))

Planes in 3D

If the vectors lie within a plane with a known normal vector n, their rotation axis lies along n. Adapting the 2D computation while incorporating n provides the clockwise angle:

dot = x1*x2 + y1*y2 + z1*z2
det = x1*y2*zn + x2*yn*z1 + xn*y1*z2 - z1*y2*xn - z2*yn*x1 - zn*y1*x2
angle = atan2(det, dot)

Ensure that n is normalized for this computation.

0-360 Degree Range

Many atan2 implementations return angles in the range [-180°, 180°]. To obtain positive angles in the range [0°, 360°], add 2π to any negative result.

The above is the detailed content of How do you calculate clockwise angles between two vectors directly?. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn