How Does std::move() Handle Lvalues in C ?

What Does std::move() Do to lvalues?

std::move() is a powerful tool in C for facilitating perfect forwarding. Yet its implementation can raise a few eyebrows upon first glance. To clarify how std::move() achieves this, let's delve into the intricacies of its implementation.

Understanding the 'Move' Function

We'll start with the simplified version of the 'move' function template:

template <typename T>
typename remove_reference<T>::type&& move(T&& arg)
{ return static_cast<typename remove_reference<T>::type&&>(arg); }

Case 1: Passing an Rvalue

When std::move() is called with an rvalue (a temporary object or an expression that evaluates to an rvalue), the move template is instantiated as follows:

// move with [T = Object]:
remove_reference<Object>::type&& move(Object&& arg)
{ return static_cast<remove_reference<Object>::type&&>(arg); }

Since remove_reference