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Method Chaining for List Reversal
When working with lists, it's often desirable to create a reversed copy without explicitly using a separate statement. However, the built-in list.reverse() method returns None and modifies the list in-place.
The Issue
Consider the following code:
k = ['F', ' ', 'B', 'F'] def solution(formation): return (formation.index(bCamel) > (len(formation) - 1 - (formation.reverse()).index(fCamel))) solution(k)
This code attempts to compare the indices of two characters (bCamel and fCamel) in a list that has been reversed. However, it raises an AttributeError because list.reverse() returns None, leaving (formation.reverse()) as None.
Solution: Using Slicing
Instead of relying on list.reverse(), you can use slicing to obtain a reversed list:
reversed_formation = formation[::-1]
The syntax [::-1] reverses the list without modifying it in-place. You can then use reversed_formation as needed:
def solution(formation): reversed_formation = formation[::-1] return (formation.index(bCamel) > (len(formation) - 1 - reversed_formation.index(fCamel)))
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