Java Generics: extends T> vs.
Java generics allow you to create type-safe collections and methods that can operate on a range of data types. When using generics, understanding the difference between extends T> and
Consider the following example:
Map<string class extends serializable>> expected = null; Map<string class>> result = null; assertThat(result, is(expected));</string></string>
This example generates a compilation error with the following message:
Error: cannot find symbol method assertThat(java.util.Map<java.lang.string>>, org.hamcrest.Matcher<java.util.map extends java.io.serializable>>>)</java.util.map></java.lang.string>
Why does this version fail to compile?
The reason lies in the use of
What is the downside of changing assertThat to Matcher extends T>?
Changing assertThat to Matcher extends T> allows us to pass in a Matcher that matches a supertype of T. While this may seem like a simple change, it can lead to unexpected behavior. For instance, if we have a Matcher that matches a List of Strings, we could pass it to a method that expects a Matcher for a List of Objects. In this case, the Matcher would not be able to correctly match the actual parameter, potentially leading to incorrect results.
Is there a point to genericizing the assertThat method in JUnit?
The genericizing of assertThat in JUnit aims to ensure type safety and prevent mismatches between expected and actual types. However, as discussed above, it can also lead to potential issues if not used carefully.
Recommendation
When deciding between extends T> and
- Use extends T> when the method requires a supertype of T to be passed in.
- Use
when the method requires an exact type match for T.
By following these recommendations, you can avoid compilation errors and ensure type safety when using Java generics.
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