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Is a Class a Template Specialization?
In C , it can be useful to determine if a given type is a specialization of a particular class template. For instance, consider the following code:
template<class t> struct A {}; template<class comparet> void compare() { // is this A? cout , CompareT >::value ???? }</class></class>
Given the above code, how can we verify if CompareT is an A for some type *?
Solution:
Utilizing the is_specialization template metafunction, you can check if a type is a specialization of a class template. Here's an example:
template<class t template> class Template> struct is_specialization : std::false_type {}; template<template> class Template, class... Args> struct is_specialization<template>, Template> : std::true_type {}; static_assert(is_specialization<:vector>, std::vector>{}, ""); static_assert(!is_specialization<:vector>, std::list>{}, "");</:vector></:vector></template></template></class>
In the above example, is_specialization takes two arguments: T and Template. If T is a specialization of Template, is_specialization
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