Determining Integerity of Float Values
In this code snippet, you're seeking the largest cube root that is a whole number, less than 12,000:
processing = True n = 12000 while processing: n -= 1 if n ** (1/3) == #checks to see if this has decimals or not
To verify if a float value is an integer, you can utilize the float.is_integer() method:
>>> (1.0).is_integer() True >>> (1.555).is_integer() False
Note that in Python 2, 1/3 results in 0 due to floor division for integer operands, and floating-point arithmetic can be inexact. Adjusting the loop with this in mind:
for n in range(12000, -1, -1): if (n ** (1.0/3)).is_integer(): print n
We obtain the expected results:
27 8 1 0
However, due to the imprecision of floating-point arithmetic, numbers higher than 3 cubed (including 10648) are omitted. To address this, you can check for numbers close to the whole number instead:
import math for n in range(12000, -1, -1): if math.isclose((n ** (1.0/3)), round(n ** (1.0/3))): print n
This variation outputs:
10648 27 8 1 0
For Python 3.5 and later, you can utilize the math.isclose() function to check if a floating-point value is within a customizable margin.
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