Home >Backend Development >PHP Tutorial >Why am I getting the 'Trying to access array offset on value of type null' error in PHP?

Why am I getting the 'Trying to access array offset on value of type null' error in PHP?

Patricia Arquette
Patricia ArquetteOriginal
2024-11-12 22:07:021069browse

Why am I getting the

Trying to Access Array Offset on Value of Type Null Error in PHP: Addressing the Issue

The "Trying to access array offset on value of type null" error in PHP arises when an attempt is made to access an array element that does not exist. This error typically occurs when a database query results in an empty array or a null value.

Understanding the Error

In PHP, database fetching functions return either null or an empty array when there are no matching records or when the result set has been exhausted. Consequently, it is crucial to check for the existence of data before accessing array elements.

Resolving the Issue

To resolve this error, employ one of the following techniques:

1. Explicitly Checking for Data Existence:

$monday_lectures = "SELECT * from lectures where lecture_time = '11am to 1pm' and lecture_day = 'firday'";
$result_11to1 = mysqli_query($con, $monday_lectures);
$m11to1 = mysqli_fetch_array($result_11to1);
if ($m11to1 && $m11to1["lecture_day"] !== '') {
    echo "<td>".$m11to1["lecture_name"]."</td>";
} else {
    echo "<td> no class</td>";
}

2. Using Null Coalescing Operator:

$monday_lectures = "SELECT * from lectures where lecture_time = '11am to 1pm' and lecture_day = 'firday'";
$result_11to1 = mysqli_query($con, $monday_lectures);
$m11to1 = mysqli_fetch_array($result_11to1);
$lecture = $m11to1["lecture_day"] ?? null;

This approach allows you to specify a default value for the array element if it does not exist.

The above is the detailed content of Why am I getting the 'Trying to access array offset on value of type null' error in PHP?. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn