Home >Backend Development >Golang >Why is Sqlmock Failing to Match My Query Despite Identical Output in the Log?

Why is Sqlmock Failing to Match My Query Despite Identical Output in the Log?

Linda Hamilton
Linda HamiltonOriginal
2024-11-12 16:59:02264browse

Why is Sqlmock Failing to Match My Query Despite Identical Output in the Log?

Sqlmock Not Matching Query Despite Identity in Log Output

Error Message

When attempting to match a query in a Gorm test using sqlmock, the following error is encountered:

(path/to/my/project/database.go:263)
[2020-01-08 10:29:40]  Query: could not match actual sql: "SELECT * FROM "storage_pools" WHERE "storage_pools"."deleted_at" IS NULL AND ((poolid = ?)) ORDER BY "storage_pools"."id" ASC LIMIT 1" with expected regexp "SELECT * FROM "storage_pools" WHERE "storage_pools"."deleted_at" IS NULL AND ((poolid = ?)) ORDER BY "storage_pools"."id" ASC LIMIT 1"

Resolution

The issue stems from the use of regexp as the sqlmock query matcher. By default, sqlmock uses a strict equality query matcher, which requires an exact match between the actual query and the expected pattern.

To solve this, use the QueryMatcherEqual option to replace the default query matcher:

QueryMatcherOption(sqlmock.QueryMatcherEqual)

Additional Considerations

  • Ensure that the sqlmock query matches the actual query string, including any special characters that may need to be escaped.
  • If the query includes literal values, use WithArgs() to specify the arguments and escape them as necessary.
  • If the query includes functions or complex conditions, use regexp.QuoteMeta() to convert it to a regular expression that sqlmock can match.

The above is the detailed content of Why is Sqlmock Failing to Match My Query Despite Identical Output in the Log?. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn