Why Do Uninitialized Variables in C Behave Unpredictably?

Understanding the Behavior of Uninitialized Variables in C

In C , the behavior of uninitialized variables can be confusing. While it's true that uninitialized variables are typically assigned garbage values, this is not always the case. Instead, the default behavior of uninitialized local variables (i.e., those defined within a function) is for their value to be indeterminate.

Consider the following code:

int main() {
    int a;
    cout <p>In this example, the variable 'a' is declared but not initialized. Since it is a local variable, its value is indeterminate. However, when 'a' is used in the cout statement, it introduces undefined behavior. In this case, the program happened to output 0, but this is not guaranteed. Undefined behavior can lead to unexpected results and crashes.</p><p>On the other hand, non-local and thread-local variables are zero-initialized by default. This means they will always start with a value of 0, even if they are not explicitly assigned. However, this does not apply to local variables, as demonstrated in the example above.</p><p>It is generally considered good practice to initialize variables explicitly to avoid the potential hazards of indeterminate and undefined behavior. By setting variables to specific values when declaring them, you can ensure predictable program behavior and reduce the risk of errors.</p>

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