How to Resolve "OUT or INOUT argument ... is not a variable" Error When Calling Stored Procedures with PDO?

Calling Stored Procedure with Out Parameter Using PDO

This question explores an issue encountered while trying to call a stored procedure with an output parameter using PDO in PHP. The error message "SQLSTATE[42000]: Syntax error or access violation: 1414 OUT or INOUT argument 1 for routine mydb.proc_OUT is not a variable or NEW pseudo-variable in BEFORE trigger" arises.

To resolve this issue, the following steps are suggested:

1. Use a separate query for retrieving the output parameter: Instead of binding the output parameter directly, execute another query to retrieve the value of the output parameter after executing the stored procedure. For example:

$dbh->query("CALL SomeStoredProcedure($someInParameter1, $someInParameter2, @someOutParameter)");
$dbh->query("SELECT @someOutParameter");

2. Insert "SELECT @someOutParameter" in the stored procedure: Alternatively, insert "SELECT @someOutParameter" into the stored procedure and then bind the result to the output parameter using prepared statements. For example:

$stmt = $dbh->prepare("CALL SomeStoredProcedure(?, ?)");
$stmt ->execute(array($someInParameter1, $someInParameter2));

By implementing these solutions, the error related to the output parameter in the stored procedure should be resolved.

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