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Template Deduction for Function Based on Its Return Type: An Exploration
Introduction
In C , template deduction allows the compiler to infer the type arguments when invoking a templated function based on the actual arguments provided. This can simplify code by removing the need to explicitly specify type arguments.
The Proposed Scenario
The given problem presents a scenario where the user desires to use template deduction to allocate memory for objects of different types using a generic Allocate function. Specifically, they wish to achieve the following code:
<code class="cpp">GCPtr<A> ptr1 = GC::Allocate(); GCPtr<B> ptr2 = GC::Allocate();</code>
Instead of the current implementation:
<code class="cpp">GCPtr<A> ptr1 = GC::Allocate<A>(); GCPtr<B> ptr2 = GC::Allocate<B>();</code>
Templating the Allocate Function
The current Allocate function template is defined as follows:
<code class="cpp">template <typename T> static GCPtr<T> Allocate();</code>
However, it's not possible to achieve the desired template deduction using solely the return type. The type deduction process primarily relies on the function's arguments.
A Workaround with Helper Function
To overcome this limitation, a helper function can be employed to hide the explicit type argument as shown below:
<code class="cpp">// Helper function template <typename T> void Allocate( GCPtr<T>& p ) { p = GC::Allocate<T>(); } // Usage int main() { GCPtr<A> p = 0; Allocate(p); }</code>
Alternative Syntax with C 11
C 11 introduces a syntax that allows discarding the explicit type declaration during template deduction:
<code class="cpp">auto p = GC::Allocate<A>(); // p is of type GCPtr<A></code>
Conclusion
While it's not possible to solely rely on template deduction via the return type, using a helper function or the C 11 syntax can provide a convenient alternative that aligns with the desired behavior. These techniques enable the allocation of different types of objects with simplified syntax, reducing the need for explicit type arguments.
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