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When employing the std::function template, ambiguity can arise due to multiple plausible overloads. Specifically, consider the following code snippet:
<code class="cpp">#include <functional> using namespace std; int a(const function<int()>& f) { return f(); } int a(const function<int(int)>& f) { return f(0); } int x() { return 22; } int y(int) { return 44; } int main() { a(x); // Call is ambiguous. a(y); // Call is ambiguous. }</code>
The ambiguity stems from the fact that both function
The signature of the template argument for std::function is considered part of its type during declaration and definition. However, this is not the case during object construction.
std::function, like many functional objects in C , uses a technique called type erasure. This enables it to accept arbitrary objects or functions, as long as they satisfy the expected signature when called. The downside is that errors related to mismatched signatures occur deep within the implementation, rather than at the constructor level.
Three primary options exist for circumventing this ambiguity:
While the template argument of std::function does determine its type during declarations and definitions, it plays no role in object construction. This can lead to ambiguity when constructors accept arbitrary arguments. To resolve this, programmers can use explicit type casting, function object wrapping, or TMP.
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