How to Pass a Two-Dimensional Array Reference to a Function in C ?

Passing a Two-Dimensional Array Reference to a Function in C

You're attempting to pass a reference to a two-dimensional array in C . The issue arises because your function prototype has syntax errors, specifically the "&" before "". This error indicates a missing comma or ellipsis before the "".

To correct this:

1. Ensure Reference to the Array: Use the following function prototype:

void do_something(int (&array)[board_width][board_height]);

This declares array as a reference to the two-dimensional array, allowing you to access and modify its elements directly.

2. Understand Reference Parameters: When passing a reference parameter, the actual array is passed by reference, not a copy. Therefore, any changes made to the array within the function will be reflected outside of it.
3. Determining Array Size: If you know the dimensions at compile time, as you've indicated, you can specify them in the function prototype. This is crucial for reference parameters, as the compiler needs to know the exact size of the array.
4. Alternative Method (Pointer to Array): An alternative approach is to declare the function parameter as a pointer to the array:

void do_something(int array[board_width][board_height]);

However, this will pass a pointer to the first sub-array of the two-dimensional array. The compiler will ignore the "board_width" dimension, which may not be desirable if you require direct access to all elements.

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