Home >Backend Development >Python Tutorial >How Can We Split Text Without Spaces Into a List of Words?
This article delves into the complexities of efficiently splitting a text string devoid of spaces into a meaningful list of words. We explore an algorithm that leverages word frequency to achieve accurate results for real-world data.
The algorithm operates under the assumption that words are independently distributed, following Zipf's law. This implies that the probability of encountering a word with rank 'n' in a dictionary is approximately 1/(n log N), where N represents the total number of words in the dictionary.
To infer the position of spaces, we employ dynamic programming. We define a cost function that utilizes the logarithm of the inverse of word probability. The optimal sentence maximizes the product of individual word costs, which can be efficiently computed using dynamic programming.
The following Python code implements the algorithm:
<code class="python">import math words = open("words-by-frequency.txt").read().split() wordcost = dict((k, log((i+1)*log(len(words)))) for i,k in enumerate(words)) maxword = max(len(x) for x in words) def infer_spaces(s): cost = [0] for i in range(1,len(s)+1): c,k = best_match(i) cost.append(c) out = [] i = len(s) while i>0: c,k = best_match(i) out.append(s[i-k:i]) i -= k return " ".join(reversed(out))</code>
Using the provided code, we can split a text string without spaces and obtain meaningful words:
s = 'thumbgreenappleactiveassignmentweeklymetaphor' print(infer_spaces(s))
The algorithm effectively infers the location of spaces, resulting in accurate word recognition for both short and long text strings. Even in the absence of explicit delimiters, the output maintains a high level of coherence and readability.
The algorithm offers several benefits:
The above is the detailed content of How Can We Split Text Without Spaces Into a List of Words?. For more information, please follow other related articles on the PHP Chinese website!