How to Pass Variable Parameters to Sprintf in Go with a Slice of Strings?

Passing Variable Parameters to Sprintf in Go

When working with a large number of parameters, manually passing them to Sprintf can be tedious. Fortunately, there is a way to simplify this process.

Issue:

Attempting to pass a slice of strings ([]string) directly to Sprintf results in an error:

cannot use v (type []string) as type []interface {} in argument to fmt.Printf

Solution:

To resolve this error, declare the slice as a type of []interface{} instead of []string. Sprintf expects an array of interface{} parameters, as seen in its signature:

func Printf(format string, a ...interface{}) (n int, err error)

Example:

s := []interface{}{"a", "b", "c", "d"}
fmt.Printf("%5s %4s %3s\n", s[1], s[2], s[3])

v := s[1:]
fmt.Printf("%5s %4s %3s\n", v...)

Output (Go Playground):

b    c   d
b    c   d

Note:

[]interface{} and []string are not interchangeable. If you have an existing []string, you can manually convert it to []interface{} as follows:

ss := []string{"a", "b", "c"}
is := make([]interface{}, len(ss))
for i, v := range ss {
    is[i] = v
}

The above is the detailed content of How to Pass Variable Parameters to Sprintf in Go with a Slice of Strings?. For more information, please follow other related articles on the PHP Chinese website!