How to Determine if a Go File is Executable?

How to Determine Executable File Status in Go

Given an os.FileInfo instance, you may need to check if a file is executable in Go. This requires deciphering the permission bits from os.FileInfo.Mode().

Test Case:

#!/usr/bin/env bash
mkdir -p test/foo/bar
touch test/foo/bar/{baz.txt,quux.sh}
chmod +x test/foo/bar/quux.sh

<code class="go">import (
    "os"
    "path/filepath"
    "fmt"
)</code>

Solution:

The file's executability is determined by the Unix permission bits stored in os.FileMode.Perm(). These bits form a 9-bit bitmask (0777 octal).

Unix Permission Bit Meaning:

rwxrwxrwx

For Each User Class:

• Owner: Bitmask 0100
• Group: Bitmask 0010
• Others: Bitmask 0001

Functions to Check Executability:

• Executable by Owner:

  <code class="go">func IsExecOwner(mode os.FileMode) bool {
    return mode&0100 != 0
  }</code>

• Executable by Group:

  <code class="go">func IsExecGroup(mode os.FileMode) bool {
    return mode&0010 != 0
  }</code>

• Executable by Others:

  <code class="go">func IsExecOther(mode os.FileMode) bool {
    return mode&0001 != 0
  }</code>

• Executable by Any:

  <code class="go">func IsExecAny(mode os.FileMode) bool {
    return mode&0111 != 0
  }</code>

• Executable by All:

  <code class="go">func IsExecAll(mode os.FileMode) bool {
    return mode&0111 == 0111
  }</code>

<code class="go">func main() {
    filepath.Walk("test", func(path string, info os.FileInfo, err error) error {
        if err != nil || info.IsDir() {
            return err
        }
        fmt.Printf("%v %v", path, IsExecAny(info.Mode().Perm()))
    }
}</code>

Expected Output:

test/foo/bar/baz.txt false
test/foo/bar/quux.txt true

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