Why Does Java Use \'extends\' for Type Parameter Bounds Instead of \'implements\'?

Java's Distinctive Use of "extends" for Type Parameter Bounds

In Java, defining bounds on type parameters adheres to a specific convention that departs from the common "implements" syntax used in other languages. This article delves into the reasoning behind this peculiarity.

Background:

Type parameters allow developers to create generic classes and interfaces that can accept any type as an argument. To ensure type safety, constraints can be defined on these parameters, specifying the types they must adhere to.

The Conundrum:

In Java, the "implements" keyword is reserved for declaring that a class implements a specific interface. However, it cannot be used to bound type parameters. For instance, the following code is prohibited:

public interface C {}
public class A<B implements C>{} 

The Explanation:

Unlike "implements," Java uses "extends" for defining upper bounds of type parameters. This syntax implies that the parameter type must be a subtype of the specified type. Conversely, "super" is used for lower bounds, indicating that the parameter type must be a supertype of the specified type.

This convention ensures clarity and consistency in the generic constraint language. Using "extends" for both upper and lower bounds simplifies the syntax and reduces ambiguity.

Implications:

By limiting the use of "implements" to class-interface relationships, Java prevents confusion between interface implementation and type parameter constraints. Developers can unambiguously declare whether a class implements an interface or if its type parameter has a specific bound.

Conclusion:

Java's distinct use of "extends" for type parameter bounds stems from a desire for clarity and coherence in defining generic types. It distinguishes between interface implementation and type constraints, ensuring a consistent and unambiguous syntax for developers.

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