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ES6 Destructuring Function Parameters: Naming the Root Object
In ES6, destructuring function parameters allows you to extract specific properties from an object and directly assign them to variables within the function. However, if you require the original object's name for further processing, it can pose a challenge.
Retaining the Root Object's Name
In ES5, the root object's name can be passed explicitly to subclasses by passing the entire object. However, this approach is not feasible with ES6 destructuring, which only extracts specific properties.
Extracting Root Object Properties
To work around this issue, one option is to extract all necessary properties from the root object in the subclass. This method becomes cumbersome with a large number of properties.
Using a Variable to Hold the Root Object
A more concise solution is to create a variable to hold the root object. While this adds an extra line of code, it provides a clean and flexible way to access the original object and simplifies operation in more complex scenarios.
const setupChildClass6 = options => { const {minVal, maxVal} = options; rangeSlider.setup(minVal, maxVal); setupParentClass6(options); // Root object can be accessed as 'options' };
This method allows you to pass the entire root object to the parent class and still access specific properties within the subclass. It provides a balance between code conciseness and flexibility.
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