Home > Article > Backend Development > Why Does Passing Non-Const References to `std::async` Result in Compilation Errors?
In attempting to pass a non-const reference as an argument to std::async, developers may encounter compilation errors like the one mentioned in the original query. This article delves into the reasoning behind this failure and the underlying design choices involved.
std::async is a powerful tool for executing tasks asynchronously, but its behavior can be confusing when passing reference arguments. Consider the following example:
<code class="cpp">void foo(int& value) {} int main() { int value = 23; std::async(foo, value); // Error: no type named 'type' in 'class std::result_of<void (*(int))(int&>)>' }</code>
This code fails to compile with an ambiguous reference_wrapper. Why does this happen?
The reason for this behavior lies in a deliberate design choice. std::async intentionally makes copies of all arguments by default to ensure safety. This approach prevents potential issues related to dangling references and race conditions.
In certain scenarios, however, passing arguments by reference is necessary. To accommodate this need, std::ref function exists as an explicit opt-in mechanism for reference semantics. By wrapping an argument in std::ref, developers can explicitly indicate that they understand the potential risks and take responsibility for handling them.
The design choice to copy by default and fail to pass to non-const lvalue references is rooted in safety considerations. std::async cannot reliably determine whether the function being called takes its arguments by reference or not, and it prioritizes safety over convenience.
Understanding the design choices behind std::async's behavior is crucial for using it effectively. By default, passing reference arguments is disallowed to prevent potential issues. However, when reference semantics are truly necessary, std::ref provides a controlled way to pass them while acknowledging the potential risks.
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