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HomeBackend DevelopmentPHP TutorialWhy Are My Guzzle Exceptions Still Unhandled Even With a try/catch Block?

Why Are My Guzzle Exceptions Still Unhandled Even With a try/catch Block?

Guzzle exceptions handling

In your attempt to catch exceptions thrown by Guzzle during API testing, you've encountered persistent unhandled exception errors despite implementing a try/catch block. Let's delve into your query and explore some practical solutions.

In the code snippet you provided, you have included event listeners to handle specific HTTP response codes (401, 500, etc.). However, the exception types you are catching in the try/catch block (ClientErrorResponseException, ServerErrorResponseException, BadResponseException) are not specific enough to encapsulate all the possible exceptions that could be thrown by Guzzle.

To address this issue, one approach is to disable exceptions for Guzzle, allowing you to access all status codes without triggering exceptions. This can be achieved by adding the following configuration to your client:

$client = new \Guzzle\Http\Client($httpBase, array(
  'request.options' => array(
     'exceptions' => false,
   )
));

With exceptions disabled, you can manually check the status code of the response and handle any unexpected or erroneous codes:

$request = $client->get($uri);
$response = $request->send();
$statuscode = $response->getStatusCode();

if ($statuscode > 300) {
  // Handle error conditions
}

Alternatively, you can explicitly define the expected status codes and handle them accordingly:

if (200 === $statuscode) {
  // Handle 200 OK
}
elseif (304 === $statuscode) {
  // Handle 304 Not Modified
}
elseif (404 === $statuscode) {
  // Handle 404 Not Found
}
else {
  throw new Exception("Invalid response from API...");
}

By disabling exceptions and manually handling status codes, you gain granular control over error handling and can respond appropriately to different HTTP responses.

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