Home >Backend Development >C++ >How Does `std::shared_ptr` Preserve Object Destruction Behavior Despite Type Erasure?
std::shared_ptr
The inquiry revolves around the puzzling functionality of std::shared_ptr
<code class="cpp">#include <memory> #include <iostream> #include <vector> int main() { std::cout << "At begin of main.\ncreating std::vector<std::shared_ptr<void>>" << std::endl; std::vector<std::shared_ptr<void>> v; { std::cout << "Creating test" << std::endl; v.push_back(std::shared_ptr<test>(new test())); std::cout << "Leaving scope" << std::endl; } std::cout << "Leaving main" << std::endl; return 0; }</code>
The code exhibits the following output:
At begin of main. creating std::vector<std::shared_ptr<void>> Creating test Test created Leaving scope Leaving main Test destroyed
Understanding Type Erasure
The key to this behavior lies in the type erasure performed by std::shared_ptr. When initializing a new instance, std::shared_ptr stores an internal deleter function. This function, by default, invokes the delete operator upon destruction of the shared_ptr. This mechanism ensures that the destructor of the object pointed to is invoked at the appropriate time, regardless of the type of the shared_ptr.
Consequence of Casting
Casting a std::shared_ptr
Standard Compliance and Future Implications
Regarding the guaranteed behavior of this technique, it's crucial to note that the internal implementation of std::shared_ptr may vary across different compilers and platforms. While type erasure has been a fundamental aspect of shared_ptrs, future changes to its implementation may potentially impact the described functionality.
Therefore, relying solely on this behavior is not a recommended practice and should be avoided in production code. Instead, alternative approaches, such as using std::function or a custom deleter class, are more robust and will provide consistent behavior across various implementations.
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