Error: The Specified Child Already Has a Parent (Android)
Problem:
Frequently switching between two layouts results in the following error:
FATAL EXCEPTION: main java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.
Code Snippet:
<code class="java">tv = new TextView(getApplicationContext()); // initialized elsewhere et = new EditText(getApplicationContext()); // initialized elsewhere private void ConsoleWindow() { runOnUiThread(new Runnable() { @Override public void run() { // MY LAYOUT: setContentView(R.layout.activity_console); // LINEAR LAYOUT LinearLayout layout = new LinearLayout(getApplicationContext()); layout.setOrientation(LinearLayout.VERTICAL); setContentView(layout); // TEXTVIEW layout.addView(tv); // ERROR IN THIS LINE DURING 2ND RUN // EDITTEXT et.setHint("Enter Command"); layout.addView(et); } }); }</code>
Solution:
The error message suggests removing the child (TextView) from its current parent before adding it to the new layout.
Add the following code before layout.addView(tv);:
<code class="java">if (tv.getParent() != null) { ((ViewGroup) tv.getParent()).removeView(tv); // Fix }</code>
This ensures that the TextView is properly removed from any existing parent before being added to the new layout, preventing the specified parent conflict.
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