How Can You Efficiently Find Matching (Key, Value) Pairs in Two Python Dictionaries?

Comparing Dictionaries and Identifying Matching (Key, Value) Pairs

In Python, comparing two dictionaries often involves inspecting each key-value pair to determine if they possess identical values. Here's a revised approach that addresses code elegance:

<code class="python">def compare_dictionaries(dict1, dict2):
    matched_pairs = 0
    for key, value in dict1.items():
        if key in dict2 and value == dict2[key]:
            matched_pairs += 1
    return matched_pairs</code>

Breakdown:

• The compare_dictionaries function takes two dictionaries as arguments.
• It iterates over each key-value pair in the first dictionary.
• For each key, it checks if it exists in the second dictionary and if the corresponding values are equal.
• If both conditions are met, the counter matched_pairs is incremented.
• Finally, the function returns the count of matching key-value pairs.

This approach avoids the use of zip and tuple comparisons, resulting in more concise and readable code. It also allows you to handle the case where the dictionaries have different keys gracefully.

Updated for Counting

To determine the count of matching key-value pairs, you can replace the incrementing line in the above function:

<code class="python">if key in dict2 and value == dict2[key]:
    matched_pairs += 1</code>

with:

<code class="python">if key in dict2 and dict2[key] == value:
    return 1</code>

This will cause the function to return 1 when a matching pair is found, and 0 otherwise. You can then sum the results to obtain the total count of matches.

The above is the detailed content of How Can You Efficiently Find Matching (Key, Value) Pairs in Two Python Dictionaries?. For more information, please follow other related articles on the PHP Chinese website!