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HomeBackend DevelopmentPython TutorialHow do Nested List Comprehensions in Python Work and What are Their Equivalents in Loop Form?

How do Nested List Comprehensions in Python Work and What are Their Equivalents in Loop Form?

Understanding Nested List Comprehension

List comprehensions offer a concise and elegant syntax for manipulating collections in Python. By combining nested for loops, one can construct complex data structures with ease. Here's a detailed breakdown of how nested list comprehensions work:

Consider the given list comprehension:

<code class="python">[(min([row[i] for row in rows]),max([row[i] for row in rows])) 
for i in range(len(rows[0]))]</code>

This code is equivalent to the following loop:

<code class="python">result = []
for i in range(len(rows[0])):
  innerResult = []
  for row in rows:
    innerResult.append(row[i])
  innerResult2 = []
  for row in rows:
    innerResult2.append(row[i])
  tuple = (min(innerResult), max(innerResult2))
  result.append(tuple)</code>

In general, a nested list comprehension of the form:

<code class="python">[exp2([exp1 for x in xSet]) for y in ySet]</code>

can be translated to:

<code class="python">result = []
for y in ySet:
  innerResult = []
  for x in xSet:
    innerResult.append(exp1)
  exp2Result = exp2(innerResult)
  result.append(exp2Result)</code>

For simpler cases, such as:

<code class="python">[exp1 for x in xSet for y in ySet] </code>

it is equivalent to:

<code class="python">result = [] 
for x in xSet:
  for y in ySet: 
    result.append(exp1)</code>

whereas,

<code class="python">[[exp1 for x in xSet] for y in ySet]</code>

is equivalent to:

<code class="python">result = []
for y in ySet:
  innerResult = []
  for x in xSet:
    innerResult.append(exp1)
  result.append(innerResult)</code>

It's important to note that the nesting of for loops in a single list comprehension is always from left to right. For example:

<code class="python">[item for item in row for row in matrix] </code>

This code will not work because the inner loop variable 'row' is not defined in the outer loop. The correct form is:

<code class="python">[item for row in matrix for item in row] </code>

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