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How to Resolve "General error: 2006 MySQL server has gone away" While Inserting Records
Introduction:
Inserting data into a MySQL database can occasionally result in the error "General error: 2006 MySQL server has gone away." This error occurs when the connection to the server is lost, typically due to one of two variables in the MySQL configuration.
Solution:
The key to resolving this error is to adjust the wait_timeout and interactive_timeout variables. These variables control the maximum time that MySQL will wait before terminating an inactive connection.
Adjusting Timeout Variables:
Example in PHP:
<code class="php"><?php $db = new db(); $results = $db->query("SHOW VARIABLES LIKE '%timeout%'", TRUE); echo "<pre class="brush:php;toolbar:false">"; var_dump($results); echo ""; $results = $db->query("SET session wait_timeout=28800", FALSE); // UPDATE - this is also needed $results = $db->query("SET session interactive_timeout=28800", FALSE); $results = $db->query("SHOW VARIABLES LIKE '%timeout%'", TRUE); echo "
"; var_dump($results); echo ""; class db { public $mysqli; public function __construct() { $this->mysqli = new mysqli(DB_SERVER, DB_USER, DB_PASS, DB_NAME); if (mysqli_connect_errno()) { exit(); } } public function __destruct() { $this->disconnect(); unset($this->mysqli); } public function disconnect() { $this->mysqli->close(); } function query($q, $resultset) { /* create a prepared statement */ if (!($stmt = $this->mysqli->prepare($q))) { echo("Sql Error: " . $q . ' Sql error #: ' . $this->mysqli->errno . ' - ' . $this->mysqli->error); return false; } /* execute query */ $stmt->execute(); if ($stmt->errno) { echo("Sql Error: " . $q . ' Sql error #: ' . $stmt->errno . ' - ' . $stmt->error); return false; } if ($resultset) { $result = $stmt->get_result(); for ($set = array(); $row = $result->fetch_assoc();) { $set[] = $row; } $stmt->close(); return $set; } } }
Additional Considerations:
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