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Converting uint64 to int64 without Information Loss
The provided code indeed converts the given uint64 value to an int64, but the resulting value (-1) is not the expected statistical representation. This is because, despite maintaining the bit values, the int64 data type interprets them with a different sign convention.
To avoid this discrepancy, you can use an encoder-decoder approach to preserve the original bit pattern. However, it's important to note that the conversion from uint64 to int64 using:
int64 y = int64(x)
does not alter the bit sequence. It simply applies the sign interpretation. Thus, the following conversion:
var x uint64 = 18446744073709551615 var y int64 = int64(x)
will result in:
x = 0xFFFFFFFFFFFFFFFF y = 0xFFFFFFFFFFFFFFFF (as a signed int64)
In contrast, the encoder-decoder approach ensures that the bit representation is maintained intact, regardless of the sign convention.
For example, if you modify the uint64 value slightly:
var x uint64 = 18446744073709551615 - 3
The resulting int64 conversion:
var y int64 = int64(x)
will produce:
y = -4
This demonstrates that the bit representation is preserved and interpreted accurately as a signed integer.
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