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Static Member Initialization Complications in Templated Classes
Static member initialization in C is a widely used technique, but it can become complex when dealing with templated classes. In non-templated classes, a nested helper struct can be employed for initialization, but this approach falls short when the enclosing class is templated.
Consider the following simplified example:
<code class="cpp">struct A { static std::string mA; static InitHelper mInit; static const std::string& getA() { return mA; } }; std::string A::mA; A::InitHelper A::mInit; template<class T> struct B { static std::string mB; static InitHelper mInit; static const std::string& getB() { return mB; } static InitHelper& getHelper() { return mInit; } }; template<class T> std::string B<T>::mB; template<class T> typename B<T>::InitHelper B<T>::mInit; int main() { std::cout << "A = " << A::getA() << std::endl; // Comment/uncomment lines to observe different behaviors // std::cout << "B = " << B<int>::getB() << std::endl; // [1] // B<int>::getHelper(); // [2] }</code>
Expected Behavior:
When [1] is uncommented and [2] is commented, we would expect B
Actual Behavior:
Reason for the Discrepancy:
According to the ISO/IEC C 2003 standard, the template member is implicitly instantiated when referenced in a context that requires its definition to exist. However, static data member initialization (and any associated side effects) only occur when the static data member is explicitly used. This means that if a template member is only referenced in uninstantiated templates or in other contexts that do not require its full instantiation, its static data members will not be initialized.
In the example, B
Solution:
The standard proscribes that definitions of explicitly specialized class template static data members have ordered initialization, while other class template static data members have unordered initialization. To ensure consistent initialization order, one must use explicit specializations.
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