Why Does \'Jump to Case Label\' Error Occur in a Switch Statement?

Error Resolution: "Jump to Case Label" in Switch Statement

In the provided code snippet:

</p>
<h1>include <iostream></h1>
<p>int main() <br>{</p>
<pre class="brush:php;toolbar:false">int choice;
std::cin >> choice;
switch(choice)
{
  case 1:
    int i=0;
    break;
  case 2: // error here 
}

}

the compilation error occurs because variables declared in one case label are accessible in subsequent case labels unless explicitly enclosed in a block.

In this scenario, the variable i declared in case 1 remains in scope for case 2, but its initialization code is not executed. Accessing an uninitialized variable can lead to unexpected behavior or errors.

To resolve this issue, enclose each case label within its own block:

<br> switch(choice)</p>
<pre class="brush:php;toolbar:false">{
  case 1:
    {
        int i=0;
        break;
    }
  case 2:
    {
        // Code for case 2
        break;
    }
}

This ensures that variables declared in one case are not visible or accessible outside that case. Each case now has its own isolated scope, preventing errors related to variable visibility.

The above is the detailed content of Why Does \'Jump to Case Label\' Error Occur in a Switch Statement?. For more information, please follow other related articles on the PHP Chinese website!