C Virtual Template Method
In C , it can be challenging to combine static time polymorphism (templates) with runtime polymorphism. This is evident in the following abstract class:
<code class="cpp">class AbstractComputation { public: template <class t> virtual void setData(std::string id, T data); template <class t> virtual T getData(std::string id); };</class></class></code>
This class aims to set and retrieve data of a specified type based on a unique identifier. However, a problem arises when attempting to call the generic setData function with a specific type, such as setData
The language prohibits this construct because the compiler would have to dynamically dispatch an infinite number of possible template instantiations. To resolve this issue, several approaches are possible:
Removing Static Polymorphism:
- Eliminate the static polymorphism by introducing a separate type to store the key-value mappings. The template can then resolve this at the base level, without the need for polymorphism:
<code class="cpp">class AbstractComputation { public: template <typename t> void setData( std::string const & id, T value ) { m_store.setData( id, value ); } template <typename t> T getData( std::string const & id ) const { return m_store.getData<t>( id ); } protected: ValueStore m_store; };</t></typename></typename></code>
Removing Dynamic Polymorphism:
- Retain runtime polymorphism but eliminate static polymorphism by type erasure:
- Utilize boost::any, which provides type erasure, to store data of any type:
<code class="cpp">class AbstractComputation { public: template <typename t> void setData( std::string const & id, T value ) { setDataImpl( id, boost::any( value ) ); } template <typename t> T getData( std::string const & id ) const { boost::any res = getDataImpl( id ); return boost::any_cast<t>( res ); } protected: virtual void setDataImpl( std::string const & id, boost::any const & value ) = 0; virtual boost::any getDataImpl( std::string const & id ) const = 0; };</t></typename></typename></code>
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