How can I extract the days of the week within a given week number in PHP, starting with Monday?

Calculating Days of the Week Given a Week Number

This problem aims to extract the days of the week within a given week number, specifically commencing with Monday.

PHP Solution

The following PHP code can be utilized to achieve this calculation:

<code class="php">$week_number = 40;
$year = 2008;
for ($day = 1; $day <= 7; $day++) {
    printf('%s\n', date('m/d/Y', strtotime($year . "W" . $week_number . $day)));
}

This script produces the following output for week 40:

10/06/2008
10/07/2008
10/08/2008
10/09/2008
10/10/2008
10/11/2008
10/12/2008

Alternative PHP Solution for Extracting Dates within a Week

Below is an adapted solution that operates slightly differently:

<code class="php">function week_from_monday($date) {
    list($day, $month, $year) = explode('-', $date);

    $wkday = date('l', mktime('0', '0', '0', $month, $day, $year));

    switch ($wkday) {
        case 'Monday': $numDaysToMon = 0; break;
        case 'Tuesday': $numDaysToMon = 1; break;
        case 'Wednesday': $numDaysToMon = 2; break;
        case 'Thursday': $numDaysToMon = 3; break;
        case 'Friday': $numDaysToMon = 4; break;
        case 'Saturday': $numDaysToMon = 5; break;
        case 'Sunday': $numDaysToMon = 6; break;
    }

    $monday = mktime('0', '0', '0', $month, $day - $numDaysToMon, $year);

    $seconds_in_a_day = 86400;

    for ($i = 0; $i < 7; $i++) {
        $dates[$i] = date('Y-m-d', $monday + ($seconds_in_a_day * $i));
    }

    return $dates;
}

This function accepts a date string in the format 'DD-MM-YYYY' and converts it into an array of dates representing the days in the week starting from Monday. For instance, using the date '07-10-2008' yields the following array:

Array
(
    [0] => 2008-10-06
    [1] => 2008-10-07
    [2] => 2008-10-08
    [3] => 2008-10-09
    [4] => 2008-10-10
    [5] => 2008-10-11
    [6] => 2008-10-12
)</code>

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