Home  >  Article  >  Web Front-end  >  Why do Chrome and Safari display different object values in the console compared to Firefox?

Why do Chrome and Safari display different object values in the console compared to Firefox?

DDD
DDDOriginal
2024-10-26 03:22:021009browse

Why do Chrome and Safari display different object values in the console compared to Firefox?

Different Object Display Values in Chrome, Firefox, and Safari

Upon debugging JavaScript objects in different browsers, developers may encounter discrepancies in the displayed values in the console. This article explores this issue, providing an explanation for the observed behavior.

The Issue

Consider the following JavaScript code:

var foo = {bar: 1111};
console.log(foo);
console.log(foo.bar);

foo.bar = 2222;
console.log(foo);
console.log(foo.bar);

In Firefox, the expected output is observed:

Object { bar=1111}
1111

Object { bar=2222}
2222

However, in Chrome and Safari, the output differs:

Object { bar=2222}
1111

Object { bar=2222}
2222

Explanation

This difference arises from a design decision in Chrome's (and, by extension, Safari's) browser console. When logging an object, Chrome creates a reference to the object itself. Upon clicking and opening the object tab in the console, the logged value remains constant, regardless of any subsequent changes to the object. This creates a discrepancy between the displayed value and the actual value of the object in memory.

Resolution

To resolve this issue and obtain the expected output in Chrome and Safari, developers can employ any method to serialize the object, such as JSON.stringify():

console.log(JSON.stringify(foo));

This will display the object's JSON representation, ensuring a consistent output across all browsers.

The above is the detailed content of Why do Chrome and Safari display different object values in the console compared to Firefox?. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn