How to Efficiently Remove Elements from an Array Based on Another Array in JavaScript?

Efficient Removal of Elements Based on Another Array [Duplicate]

In JavaScript, removing elements from one array that are present in another array can be a challenge. One commonly used approach involves using jQuery's grep() and inArray() methods. However, there are pure JavaScript solutions that can achieve the same result without looping or splicing.

One method is to utilize the Array.filter() method, which iterates over the array and filters out elements based on a specified condition. In this case, the condition is whether the element is not present in the toRemove array.

<code class="javascript">myArray = myArray.filter(function(el) {
  return toRemove.indexOf(el) <p>As browser support for Array.includes() has improved, it can be used to further simplify the code:</p>
<pre class="brush:php;toolbar:false"><code class="javascript">myArray = myArray.filter(function(el) {
  return !toRemove.includes(el);
});</code>

Another adaptation using arrow functions yields even more concise code:

<code class="javascript">myArray = myArray.filter((el) => !toRemove.includes(el));</code>

These methods provide an efficient and flexible way to remove elements from an array based on criteria defined in another array without the need for loops or array manipulation.

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