


Why is the super() Method Called in a Constructor?
In Java, constructor overloading allows classes to have multiple constructors with different parameter lists. When a constructor is called without explicit parameters, it implicitly calls the parent class's default (parameterless) constructor. However, in certain scenarios, explicit calls to super() become necessary.
Implicit Call to super()
All Java classes inherit from the Object class, and therefore inherit its default constructor. This means that even if you don't explicitly call super() in your constructor, the JVM will implicitly call super() without arguments.
Explicit Call to super() with Parameters
If the parent class defines constructors with parameters, you need to explicitly call super() with appropriate arguments to initialize the parent class with specific values. For example, if the parent class has a constructor that takes a string, you would use super("parameter") to initialize it.
**Example: Controlling Frame
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Java'splatformindependencemeansdeveloperscanwritecodeonceandrunitonanydevicewithoutrecompiling.ThisisachievedthroughtheJavaVirtualMachine(JVM),whichtranslatesbytecodeintomachine-specificinstructions,allowinguniversalcompatibilityacrossplatforms.Howev

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ToensureJavaplatformindependence,followthesesteps:1)CompileandrunyourapplicationonmultipleplatformsusingdifferentOSandJVMversions.2)UtilizeCI/CDpipelineslikeJenkinsorGitHubActionsforautomatedcross-platformtesting.3)Usecross-platformtestingframeworkss


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